the sum of the squares of the perpendiculars on any tangent axis each at a distance ae from the centre , is

Prove that the sum of the squares of the perpendiculars on any tangent of the ellipse form the points on the minor axis is 2a^(2)

The sum of the squares of the perpendiculars on any tangent to the ellipse a 2 x 2 ​ + b 2 y 2 ​ =1 from two points on the minor axis, each at a distances ae from the centre, is

The sum of the squares of the perpendiculars on any tangents to the ellipse (x^2)/(a^2)+(y^2)/(b^2)=1 from two points on the minor axis each at a distance a e from the center is (a) 2a^2 (b) 2b^2 (c) a^2+b^2 a^2-b^2

The sum of the squares of the perpendiculars on any tangents to the ellipse (x^2)/(a^2)+(y^2)/(b^2)=1 from two points on the minor axis each at a distance a e from the center is 2a^2 (b) 2b^2 (c) a^2+b^2 a^2-b^2

The sum of the squares of the perpendiculars on any tangents to the ellipse (x^2)/(a^2)+(y^2)/(b^2)=1 from two points on the minor axis each at a distance a e from the center is (a) 2a^2 (b) 2b^2 (c) a^2+b^2 (d) a^2-b^2

The sum of the squares of the perpendiculars on any tangent to the ellipse x^(2)//a^(2)+y^(2)//b^(2)=1 from two points on the minor axis each at a distance sqrt(a^(2)-b^(2)) from the centre is

The sum fo the squares of the perpendicular on any tangent to the ellipse x^(2)/a^(2) + y^(2)/b^(2) = 1 from two points on the mirror axis, each at a distance sqrt(a^(2) - b^(2)) from the centre, is

The sum of the squares of the perpendiculars on any tangents to the ellipse (x^(2))/(a^(2))+(y^(2))/(b^(2))=1 from two points on the minor axis each at a distance ae from the center is 2a^(2)( b) 2b^(2) (c) a^(2)+b^(2)a^(2)-b^(2)

If two points are taken on the minor axis of an ellipse (x^2)/(a^2)+(y^2)/(b^2)=1 at the same distance from the center as the foci, then prove that the sum of the squares of the perpendicular distances from these points on any tangent to the ellipse is 2a^2dot