Home
Class 12
CHEMISTRY
PCl(5) vapour decomposes on heating acco...

`PCl_(5)` vapour decomposes on heating according to the reaction :
`PCl_5 (g) hArr PCl_(3) (g) + Cl_(2)(g)`
The density of a sample of a partially dissociated `PCl_(5)` at 1.0 atm and 500 K was found 4.8 g/L . Calculate the degree of dissociated and `DeltaG^(@)` for the reaction at 500 K
(Given R=0.082 L atm `K^(-1)mol^(-1)`)
, R=8.314 `JK^(-1) mol^(-1)` , In x=2.3031 `log_(10)x`)

Promotional Banner

Similar Questions

Explore conceptually related problems

PCl_(5) vapour decomposes on heating according to the reaction : PCl_5 (g) hArr PCl_(3) (g) + Cl_(2)(g) The density of a sample of a partially dissociated PCl_(5) at 1.0 atm and 500 K was found 4.8 g/L . Calculate the degree of dissociation and DeltaG^(@) for the reaction at 500 K (Given R=0.082 L atm K^(-1)mol^(-1) ) , R=8.314 JK^(-1) mol^(-1) , In x=2.3031 log_(10)x )

PCl_(5) is 10% dissociated at 1 atm . What is % dissociation at 4 atm . PCl_(5)(g)hArr PCl_(3)(g)+Cl_(2)(g)

PCl_(5) is 10% dissociated at 1 atm. What is % dissociation at 4 atm . PCl_(5)(g)hArr PCl_(3)(g)+Cl_(2)(g)

a' moles of PCl_(5) are heated in a closed container to equilibrate PCl_(5) (g) hArr PCl_(3)(g) + Cl_(2) (g) at a pressure of p atm . If x moles of PCl_(5) dissociate at equilibrium , then

For PCl_(5 (g)) hArr PCl_(3 (g)) + Cl_(2 (g)) at equilibrium , K_(P) = P//3 . Then degree of dissociation of PCl_(5) at that temperature is

For the reaction PCl_(5)(g)hArr PCl_(3)(g)+Cl_(2)(g) , the equation connecting the degree of dissociation (alpha) of PCl_(5)(g) with the equilibrium constant K_(p) is

For the reaction PCl_(5)(g)hArr PCl_(3)(g)+Cl_(2)(g) , the equation connecting the degree of dissociation (alpha) of PCl_(5)(g) with the equilibrium constant K_(p) is