" 16."|(2x-1)/(x-1)|>2,x in R

Solve: |(2x-1)/(x-1)|gt2,x in R

(x+1)/3le(2x-1)/4,x in R

A polynomial p(x) satisfies the relation (x-16)p(2x)=16(x-1)p(x)AA x in R Let p(7)=135 then

Solve: (-1)/(|x|-2)>=1, where x in R,x!=+-2

16x^(2)=8x-1

Let f : R to R be such that, f(2x-1)=f(x) for all x in R . If f is continuous at x = 1 and f(1)=1 then-

Solve : 2|x+1|^(2)-|x+1|=3 , x in R

Solve : 2|x+1|^(2)-|x+1|=3 , x in R

(16)^(1/(x-1))=2^x/2 , then find x

Let f(x) (1-cos4x)/(x^(2)),g(x)=(sqrtx)/((sqrt(16+sqrtx))-4)and q(x)=(e^(2x)-x^(x)+1)/(x^(2x+e^(x)+1)),(x in R). lim_(x to 0)g(x)=