A force `vec(F) = hat(i) + 3 hat(j) + 2 hat(k)` acts on a particle to displace it from the point A `(hat(i) + 2hat(j) - 3 hat(k))` to the point `B(3hat(i) - hat(j)+5hat(k))`. The work done by the force will be

A force vec(F) = hat(i) + 3hat(j) + 2hat(k) acts on a particle to displace it from the point A (hat(i) + 2hat(j) - 3hat(k)) to the point B (3hat(i) - hat(j) + 5hat(k)) . The work done by the force will be

A particle acted upon by constant forces 5hat(i) + hat(j) - 2hat(k) and 2hat(i) + hat(j) - 2hat(k) is displaced from the point 2hat(i) + 2hat(j) - 4hat(k)" " "to point" " " 6hat(i) + 4hat(j) - 2hat(k). The total work done by the forces in SI unit is

If vec(F) = 3hat(i) + 4hat(j) + 5hat(k) and vec(S) = 6hat(i) + 2hat(j) + 5hat(k) , find the work done by the force.

A uniform force of ( 3hat(i)+hat(j)) N acts on an particle of mass 2 kg . Hence the particle is displaced from position (2hat(i)+hat(k)) m to position (4hat(i)+3hat(j)-hat(k)) m . The work done by the force on the particle is