`DeltaS` for freezing of 10 g of `H_(2)O(l)` (enthalpy of fusion is 80 cal/g) at `0^(@)C` and 1 atm is :

A sample of a gaseous hydrocarbon is burnt in excess oxygen. The products of the reaction are 8L of CO_(2)(g) 10 L of H_(2)O(g) , all at 0^(@)C and 1 atm pressure. The formula of the hydrocarbon is-

120 g of ice at 0^(@)C is mixed with 100 g of water at 80^(@)C . Latent heat of fusion is 80 cal/g and specific heat of water is 1 cal/ g-.^(@)C . The final temperature of the mixture is

120 g of ice at 0^(@)C is mixed with 100 g of water at 80^(@)C . Latent heat of fusion is 80 cal/g and specific heat of water is 1 cal/ g-.^(@)C . The final temperature of the mixture is

50 g of ice at 0^@C is mixed with 50 g of water at 80^@C . The final temperature of the mixture is (latent heat of fusion of ice =80 cal //g , s_(w) = 1 cal //g ^@C)

50 g of ice at 0^@C is mixed with 50 g of water at 80^@C . The final temperature of the mixture is (latent heat of fusion of ice =80 cal //g , s_(w) = 1 cal //g ^@C)

The amount of heat required to raise the temperature of 75 kg of ice at 0°C to water at 10°C is (latent heat of fusion of ice is 80 cal/g, specific heat of water is 1 cal/g °C)

The enthalpy of formation for C_(2)H_(4)(g) , CO_(2)(g) and H_(2)O(l) at 25^(@)C and 1 atm. Pressure be 52 , -394 and -286 kJ mol^(-1) respectively. The enthalpy of combustion of C_(2)H_(4)(g) will be

How much steam at 100^@C will just melt 1600 g of ice at -8^@C ? (Specific heat of ice= 0.5 (cal)/g^@C , specific heat of water= 1/cal/g^@C , latent of fusion of ice = 80 cal/g , and latent heat of vaporisation of water= 540 cal/g )