[" 1.Find the equation of the plane through the line of intersection of the "],[" planes "x+y+z=1" and "2x+3y+4z=5" which is perpendicular to the plane "],[x-y+z=0]

Find the equation of the plane through the line of intersection of the planes x+y+z=1 and 2x+3y+4z=5 which is perpendicular to x-y+z=0

Find the equation of the plane through the line of intersection of the planes x+y+z=1 and 2x+3y+4z=5 which is perpendicular to the plane x-y+z=0 Then find the distance of plane thus obtained from the point A(1,3,6) .

Find the equation of the plane through the line of intersection of the planes x+y+z=1 and 2x+3y+4z=5 which is perpendicular to the plane x-y+z=0 . Then find the distance of plane thus obtained from the point A(1,3,6) .

Find the equation of the plane through the line of intersection of the planes x+y+z=1 and 2x+3y+4z=5 , which is perpendicular to the plane x-y+z=0 . Also find the distance of the plane so obtained from the origin.

Find the equation of the plane through the intersection of the planes x+y+z=1 and 2x+3y+4z=5 which is perpendicular to the plane x-y+z=0

Find the equation of the plane through the line of intersection of the planes x+y+z=1 and which is perpendicular to the plane x-y+z=0

Find the equation of the plane through the line of intersection of the planes: x+3y-z+1=0 and x+y-2z+3=0 and perpendicular to the plane 3x-y-2z-4=0

The equation of the plane passing through the line of intersection of the planes x+y+z=6 and 2x+3y+4z+5=0 and perpendicular to the plane 4x+5y-3z=8 is