The set of values of 'a' for which `ax^(2)-(4-2a)x-8lt0` for exactly three integral values of x, is

The set of values of 'a' for which f(x)=ax^(2)+2x(1-a)-4 is negative for exactly three integral values of x, is-

The set of values of x for which x^(2)-|x+2|+x>0 is

The set of values of a for which a x^2+(a-2)x-2 is negative for exactly two integral x , is a. (0,2) b. [1,2) c. (1,2] d. (0,2]

Find the number of integral values of 'a' for which ax^(2)-(3a+2)x+2(a+1)<0,a!=0 holds exactly four integral value of x.

The set of values of 'a' for which x^2-ax+sin^-1(sin4)gt0 forallx in R is

Value (s) of 'a' for which ax^2+(a-3)x+1lt0 for at least one positive x.

If set of values a for which f(x)=ax^(2)-(3+2a)x+6a!=0 is positive for exactly three distinct negative integral values of x is (c,d], then the value of (c^(2)+4|d|) is equal to

The sum of all possible integral value of 'k' for which 5x ^(2) -2k x +1lt 0 has exactly one integral solution :

Find the number of integral values of 'a' for which ax^2 - (3a + 2)x + 2(a + 1) < 0, a != 0 holds exactly four integral value of x.

Let A denotes the set of values of x for which (x+2)/(x-4) le0 and B denotes the set of values of x for which x^2-ax-4 le 0 . If B is the subset of A then a cannot take integral value (a) 0, (b) 1 (c) 2 (d) 3