A body whose mass is 3kgs, performs rectilinear motion according to the formula `s=1+t+t^2` (s is in cm, and t is in seconds). Then the kinetic energy of the body when `t = 5` is

A body of mass 6g is in rectilinear motion according to the law s=-1+(t+1)+(t+1)^(3) (s is in centimetres and t, in seconds). Find the kinetic enery of the body one second after it begins to move.

A body whose mass is 3kg performs rectilinear motion according to the formula s = 1 + t + t^2 , where s is measured the kinetic energy 1/2 mv^2 and t in second. Determine the kinetic energy 1/2 mv^2 of the body in 5 sec after its start.

A body of mass 2 kg is executing simple harmonic motions according to the cquation 0.06 cos (100t+ pi//4 ) m, where t is in seconds. What is the maximum kinetic energy?

A body o fmass 6 kg moves in a staight line according to the equation x= t^(3)-75t , where x denotes the distance in metre and t the time in second. The force on the body at t=4s is

A body of mass 1 kg is performing linear S.H.M. its displacement x (cm) at t (second) is given by x = 6 sin (100 t + (pi) /4) .Maximum kinetic energy of the body is

The law of rectilinear motion of a body with a mass of 100 kg is s = 2t^(2) + 3t + 1 . Determine the kinetic energy (mv^(2))/(2) of the body 5s after the start

The law of rectilinear motion of a body of mass 10kg is given by s = 2t^2 + 3t + 4 . Then the kinetic energy frac{1}{2}mv^2 of the body after 5s from the start is ….....

A body of mass 1kg is moving according to the law x(t)=(5t+4t^(2)+6t^(3))m . The force acting on the body at time t=2s is

A body of mass 2 kg travels according to the law x (t) = pt + qt^(2) + rt^(3) where, q = 4m s^(-2) , p - 3m s^(-1) and r = 5m s^(-3) . The force acting on the body at t = 2s is