In Delta ABC, 1/r1^2+1/r2^2+1/r3^2+1/r^2...

In `Delta ABC, 1/r_1^2+1/r_2^2+1/r_3^2+1/r^2 =`

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In Delta ABC, 1/r1^2+1/r2^2+1/r3^2+1/r^2 =
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Show that 1/r^2+1/r1^2+1/r2^2+1/r3^2=(a^2+b^2+c^2)/Delta^2
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Show that 1/r^2+1/r1^2+1/r2^2+1/r3^2=(a^2+b^2+c^2)/Delta^2
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In Delta ABC, 1/r1^2+1/r2^2+1/r3^2+1/r^2 =
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In DeltaABC,if(1-r1/r2)(1-r1/r3)=2 then the triangle is
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A: In a Delta ABC, r1 r2 r3 =s^2 R: In an equilateral triangle , r:R...
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