1-:[1+1-:{1+1-:(1+1-:2)}]=?

What is the solution of log_(10)[1-{1-(1-x^(2))^(-1)}^(-1)]^(1/2)= 1 ?

Find the rank of A=[[1,2,-1,2],[2,2,-1,1],[-1,-1,1,-1],[2,1,-1,2]]

The domain of f(x)=sqrt(2{x}^2-3{x}+1), where {.} denotes the fractional part in [-1,1] is [-1,1]-(1/(2,1)) [-1,-1/2]uu[(0,1)/2]uu{1} [-(1,1)/2] (d) [-1/2,1]

Let A= [{:(,1,1,1),(,1,1,1),(,1,1,1):}] , B= [{:(,2,-1,-1),(,-1,2,-1),(,-1,-1,2):}] and C=3A+7B

Let A= [{:(,1,1,1),(,1,1,1),(,1,1,1):}] , B= [{:(,2,-1,-1),(,-1,2,-1),(,-1,-1,2):}] and C=3A+7B

the value of sqrt(1(1)/(2)-[1(1)/(2)-1(1)/(2)+(1(1)/(2)-1(1)/(2)-1(1)/(4))]) is

If A= [[1,1,1],[1,1,1],[1 ,1,1]] then A^(2)=