Solution set `log_4 x-log_2 y=0` and `x^2-5y^2+4=0` is

The solution set of log_(x)2 log_(2x)2 = log_(4x) 2 is :

(B) The solution set 4(log_(2)x)^(2)+1=2log_(2)y and log_(2)x^(2)gt=log_(2)y is

The solution set of log_(2)|x^(2)-4x+5|<1 is

If log_2 x+log_4 y+log_4 z=2 then x^2yz=

53, Solution set of log_x 2.log_(2x)2=log_(4x) 2 is

53, Solution set of log_(x)2.log_(2x)2=log_(4x)2 is

The solutions to the system of equations log_(5)x+log_(27)y=4 and log_(x)5-log_(y)(27)=1 are (x_(1),y_(1)) and (x_(2),y_(2)) then log_(15)(x_(1)x_(2)y_(1)y2) is

Let the solution of y log ydx+(x-log y)dy=0 is x.log y=A(log y)^(2)+c where c is constant then A=?

Solve log_4(log_3x)-log_(1//4)(log_(1//3)y)=0 and x^2+y^2=17/4 .

Solve log_4(log_3x)+log_(1//4)(log_(1//3)y)=0 and x^2+y^2=17/4 .