[" 0.If "f(x)=(2)/(x-3),g(x)=(x-3)/(x+4)," and "h(x)=-(2(2x+1))/(x^(2)+x-12)],[" then "lim_(x rarr3)[f(x)+g(x)+h(x)]" is "]

If f(x)=(2)/(x-3),g(x)=(x-3)/(x+4)," and "h(x)=-(2(2x+1))/(x^(2)+x-12)," then "lim_(xto3) [f(x)+g(x)+h(x)]" is "

If f(x)=(2)/(x-3),g(x)=(x-3)/(x+4) and h(x)=-(2(2x+1))/(x^(2)+x-12), then find lim_(x rarr3)[f(x)+g(x)+h(x)]

If f(x)=(2)/(x-3),g(x)=(x-3)/(x+4), and h(x)=-(2(2x+1))/(x^(2)+x-12) then lim_(x rarr3)[f(x)+g(x)+h(x)] is (a) -2(b)-1 (c) -(2)/(7) (d) 0

If f(x) = (2)/(x-3), g(x) = (x-3)/(x+4) and h (x) = (-2(2x + 1))/(x^(2) + x - 12) , then lim_(x rarr 3) [f(x) + g(x) + h(x)] is equal to :

If f(x)=2/(x-3),g(x)=(x-3)/(x+4) , and h(x)=-(2(2x+1))/(x^2+x-12) then lim_(x->3)[f(x)+g(x)+h(x)] is (a) -2 (b) -1 (c) -2/7 (d) 0

If f(x)=2/(x-3),g(x)=(x-3)/(x+4) , and h(x)=-(2(2x+1))/(x^2+x-12) then lim_(x->3)[f(x)+g(x)+h(x)] is (a) -2 (b) -1 (c) -2/7 (d) 0

If f(x)=2/(x-3),g(x)=(x-3)/(x+4) , and h(x)=-(2(2x+1))/(x^2+x-12) then lim_(x->3)[f(x)+g(x)+h(x)] is (a) -2 (b) -1 (c) -2/7 (d) 0

If f(x)={(3x-1),x>=1,(2x+3),x =2} then lim_(x rarr2)f(g(x))=