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Given a function 'g' continous everywher...

Given a function 'g' continous everywhere such that `int _(0) ^(1) g (t ) dt =2 and g (1)=5.` If `f (x ) =1/2 int _(0) ^(x) (x-t) ^(2)g (t)dt,` then the vlaue of `f'(1)-f'(1)` is:

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