If M = mass, L = length, T = time and I = electric current, then the demensional formula of resistance R will be given by

If M, L, T and I stand for Mass, Length, Time and electric current respectively, the dimensional formula for Capacitance is

Let epsi_0 denote the dimensional formula of the permittivity of vacuum. If M= mass , L=length , T=time and A=electric current , then dimension of permittivity is given as [M^(p)L^(q)T^(r)A^(s)] . Find the value of (p-q+r)/(s)

Let epsi_0 denote the dimensional formula of the permittivity of vacuum. If M= mass , L=length , T=time and A=electric current , then dimension of permittivity is given as [M^(p)L^(q)T^(r)A^(s)] . Find the value of (p-q+r)/(s)

If mass, length, time and electric current is represented as M, L, T, I respectively, then dimension of resistance will be .....

Given that m = mass, l = length, t = time and i = current. The dimensional formula of ml^(2)//t^(3) i are the same as that of

If "force" F, "length" L and time T are taken as fundemental unit , the dimensional formula mass will be

If "force" F, "length" L and time T are taken as fundemental unit , the dimensional formula mass will be

If "force" F, "length" L and "time T" are taken as fundamental units , the dimensional formula of mass will be