Home
Class 12
PHYSICS
A photon sensitive metallic surface emit...

A photon sensitive metallic surface emits electrons when X-rays of wavelength `lambda` fal on it. The de-Broglie wavelength of the emitted electrons is (Neglect the work function of the surface, m is mass of the electron. H=Planck's constant. C= velocity of light)

Promotional Banner

Similar Questions

Explore conceptually related problems

Electrons with de-Broglie wavelength lambda fall on the target in an X-ray tube. The cut-off wavelength of the emitted X-ray is

Electrons with de-Broglie wavelength lambda fall on the target in an X-ray tube. The cut-off wavelength of the emitted X-ray is

Electrons with de-Broglie wavelength lambda fall on the target in an X-ray tube. The cut-off wavelength of the emitted X-ray is

Electrons with de-Broglie wavelength lambda fall on the target in an X-ray tube. The cut-off wavelength of the emitted X-ray is

A photon of wavelength 6.2 nm is used to emit an electron from the ground state of Li^(2+) . Calculate de Broglie wavelength of the emitted electron .

The de-Broglie wavelength of an electron is same as the wavelength of an photon.The K.E.of photon is 'x' times the K.E.of the electron then 'x' is (M- mass of electron h Planck's constant C - Velocity of light)

The de-Broglie wavelength of an electron is same as the wavelength of an photon.The K.E.of photon is 'x' times the K.E.of the electron then 'x' is (M- mass of electron h - Planck's constant C - Velocity of light)