वृत्त `x^2+y^2-4x-6y-12=0` के प्राचलिक समीकरण ज्ञात कीजिए ।

If 4x^2+y^2=40 and xy=6,(x>0,y>0) then the value of 2x+y is: यदि 4x^2+y^2=40 और xy=6,(x>0,y>0) , 2x+y का मान ज्ञात करें :

Find the equation of tangents to x^(2)+ y^(2) -4x + 6y - 12=0 which are parallel to x + 2y -8=0 .

Discuss the relative position of the fol- lowing pair of circles. x^(2)+y^(2) - 4x - 6y - 12 = 0 x^(2) + y^(2) + 6 x+ 18 y + 26 = 0 .

The number of common tangent to the circles x^(2) + y^(2) + 4x - 6y - 12 = 0 and x^(2) + y^(2) - 8x + 10y + 5 = 0 is

The equation of the tangents to the circle x^(2)+y^(2)-4x-6y-12=0 and parallel to 4x-3y=1 are

The number of common tangents to the circles x^2+y^2-4x-6y-12=0 and x^2+y^2+6x+18y+26=0 , is :

The normal to-be circle x^2 +y^2 - 4x + 6y -12=0 passes through the point