4x+3y-4=0;6x=8-5y

Prove that the point (2,2) is equidistant from the three straight lines 4x+3y-4=0,12x-5y+12=0and3x-4y=8.

4x+3y=4,6x+5y=8

Given the four lines with the equations x+2y-3=0 , 3x+4y-7=0 , 2x+3y-4=0 , 4x+5y-6=0 , then

Given the four lines with the equations x+2y-3=0 , 3x+4y-7=0 , 2x+3y-4=0 , 4x+5y-6=0 , then

Given the four lines with the equations 'x+2y-3=0,3x+4y-7=0,2x+3y-4=0,4x+5y-6=0, then

The lines x-y-6=0, 4x-3y-20=0 and 6x+5y+8=0 are:

Given the four lines with equations x+2y-3=0, 3x+4y-7=0, 2x+3y-4=0 and 4x+5y-6=0 , then:

Show that the line x-y-6=0,4x-3y-20=0 and 6x+5y+8=0 are concurrent. Also, find their common point of intersection.

Show that the line x-y-6=0,4x-3y-20=0 adn 6x+5y+8=0 are concurrent.Also,find their common point of intersection.