" 4."log_(2)16=

log_(3)(1-(1)/(3))+log_(3)(1+(1)/(4))+log_(3)(1+(1)/(5))+...+log_(3)(1+(1)/(242)) when simplified has the value equal to: 2 b.4c.6d.log_(2)16

If log_(2)(x-16)=log_(4)(x-4) , which of the following could be the value of x ?

If log_(3){5+4log_(3)(x-1)}=2, then x is equal to 4 (b) 3 (c) 8 (d) log_(2)16

If log_(4)2+log_(4)4+log_(4)x+log_(4)16=6 then x =

log_(3)(1+(1)/(3))+log_(3)(1+(1)/(4))+log_(3)(1+(1)/(5))+...+log_(3)(1+(1)/(242)) when simplified has the value equal to: 2 (b) 4 (c) 6 (d) log _(2)16

If "log"_(4) 2 + "log"_(4) 4 + "log"_(4) 16 + "log"_(4) x = 6 , then x =

If "log"_(4) 2 + "log"_(4) 4 + "log"_(4) 16 + "log"_(4) x = 6 , then x =

If x gt 0, and log_(2) + log_(2)(sqrt(x)) + log_(2) (4sqrt(x)) + log_(2) ( 8sqrt(x)) + log_(2) (16sqrt(x)) + ….. = 4 then x =

Solve the following log_(x)16=2 :. x^2=16impliesx= pm4, Is is correct or not ?

Solve the following log_(x)16=2 :. x^2=16impliesx= pm4, Is is correct or not ?