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2arc sin""(1)/(2) +3arc tan(-1) +arc cos...

`2arc sin""(1)/(2) +3arc tan(-1) +arc cos (-(1)/(2))` ज्ञात करें

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sin[4" arc ""Tan"1/3]=

int x^(3) "arc" tan x dx .

I= int ( dx)/( ("arc" cos x)^(5) sqrt(1-x^2) ) .