`K_(p)` for the reaction, `N_(2)+3H_(2)hArr2NH_(3)` is `1.6xx10^(-4)atm^(-2)` at `400^(@)C`. What will be `K_(p)` at `500^(@)C`? Heat of reaction in this temperature range is `-25.14 kcal`.

K_(p) for the reaction N_(2) + 3H_(2) hArr 2NH_(3) , is 1.6 xx 10^(-4) atm^(-2) at 400^(@) C. What will be K_(p) at 500^(@) C ? Heat of reaction in this temperature range is-25.14 Kcal.

K_(p) for the reaction N_(2) + 3H_(2) hArr 2NH_(3) , is 1.6 xx 10^(-4) atm^(-2) at 400^(@) C. What will be K_(p) at 500^(@) C ? Heat of reaction in this temperature range is-25.14 Kcal.

K_(p) for the reaction N_(2)+3H_(2) hArr 2NH_(3) is 1.6xx10^(-4) atm^(-2) at 400^(@)C . What will be K_(p) at 500^(@)C ? The heat of reaction on this temperature is -25.14 kcal?

The equilibrium constant K_(p) , for the reaction N_(2)(g)+3H_(2)(g) hArr 2NH_(3)(g) is 1.6xx10^(-4) at 400^(@)C . What will be the equilibrium constant at 500^(@)C if the heat of reaction in this temperature range is -25.14 kcal?

The equilibrium constant K_(p) , for the reaction N_(2)(g)+3H_(2)(g) hArr 2NH_(3)(g) is 1.6xx10^(-4) at 400^(@)C . What will be the equilibrium constant at 500^(@)C if the heat of reaction in this temperature range is -25.14 kcal?

K_(p) for the reaction N_(2)+3H_(2) hArr 2NH_(3) at 400^(@)C is 1.64xx10^(-4) atm^(-2) . Find K_(c) .

(K_(c))/(K_(p)) for the reaction, N_(2)(g)+3H_(2)(g)hArr2NH_(3(g)) is