Prove that SP + S'P = 20 for the ellipse `(x^(2))/(100) + (y^(2))/(36) = 1 , S ` and S' are the two foci of the ellipse and P is any point on the ellipse

If P is a point on the ellipse (x^(2))/(36)+(y^(2))/(9)=1 , S and S ’ are the foci of the ellipse then find SP + S^1P

If P is a point on the e llip (x^(2))/(36)+(y^(2))/(9)=1 , S and S ’ are the foci of the ellipse then find SP + SP^1

If P is any point on the ellipse (x^(2))/(36) + (y^(2))/(16) = 1 , and S and S' are the foci, then PS + PS' =

P is a point on the ellipse (x^(2))/(36)+(y^(2))/(9)=1 ; S,S^(1) are the Foci of the ellipse then SP + S^(1)P =

If P is any point on the ellipse (x^(2))/(25) + (y^(2))/(9) = 1 whose foci are S and S' perimeter of Delta SPS' is

If P is any point on the ellipse x^(2)/36 +y^(2)/16=1 and S and S', are the foci, then PS+PS'equal to

If P is a point on the ellipse (x^(2))/(16) + (y^(2))/(25) = 1 whose foci are S and S', then PS + PS' = 8.

Suppose S and S' are foci of the ellipse (x^(2))/(25)+(y^(2))/(16)=1 . If P is a variable point on the ellipse and if Delta is the area (in sq. units) of the triangle PSS' then the maximum value of Delta is double of

Suppose S and S' are foci of the ellipse (x^(2))/(25) + (y^(2))/(16)= 1. If P is a variable point on the ellipse and if Delta is area of the triangle PSS' , then the maximum value of Delta is :

P((pi)/(6)) is a point on the ellipse (x^(2))/(36)+(y^(2))/(9)=1 S,S^(1) are foci of ellipse then |SP-S^(1)P|=