If `z=x+iy`, then the equation `|z+1|=|z-1|` represents

If z=x+iy, then he equation |(2z-i)/(z+1)|=m represents a circle,then m can be (1)/(2) b.1 c.2d.3

If z=x+iy, where i=sqrt(-1) , then the equation abs(((2z-i)/(z+1)))=m represents a circle, then m can be

If z=x+iy, where i=sqrt(-1) , then the equation abs(((2z-i)/(z+1)))=m represents a circle, then m can be

If z=x+iy, then the equation |(2z-i)/(z+1)|=k will be a straight line,where -

If z=x+iy, where i=sqrt(-1) , then the equation abs(((2z-i)/(z+i)))=m represents a circle, then m can be

If complex number z=x +iy satisfies the equation Re (z+1) = |z-1| , then prove that z lies on y^(2) = 4x .

If complex number z=x +iy satisfies the equation Re (z+1) = |z-1| , then prove that z lies on y^(2) = 4x .

The locus of the point z = x +iy satisfying the equation |(z-1)/(z+1)|=1 is given n=by