The normal at P cuts the axis of the parabola `y^2=4 ax` in G and S is the focus of the parabola. It `Delta SPG` is equilateral then each side is of length

The normal at 'P' cuts the axis of the parabola y^(2) =4ax in G and S is the focus of the parabola. If Delta SPG is equilateral then each side is of length.

The normal at P cuts the axis of the parabola y^(2)=4ax in G and S is the focus of the parabola.It Delta SPG is equilateral then each side is of length

If the normal at P on y^(2)= 4ax cuts the axis of the parabola in G and S is the focus then SG=

If the normal at P on y^(2)= 4ax cuts the axis of the parabola in G and S is the focus then SG=

If Q is the foot of the perpendicular from a point P on the parabola y = 8(x-3) to its directrix. S is the focus of the parabola and if SPQ is an equilateral triangle then the length of the side of the triangle is

The normal at a point P to the parabola y^2=4ax meets axis at G. Q is another point on the parabola such that QG is perpendicular to the axis of the parabola. Prove that QG^2−PG^2= constant