The amount of steam at `100^@ C` that should be passed into `600 g` of water at `10^@ C` to make the final temperature as `40^@ C` will be

Calcualte the mass of stea that should be passed though 60 g of water at 20^(@)C , such that the final temperature is 40^(@)C . (take specific latent heat of steam is 2250 J g^(-1) ).

If 10 g of the ice at 0^@C is mixed with 10g of water at 100^@ C , then the final temperature of the mixture will be

If 10 g of ice at 0^@C mixes with 10 g of water at 10^@C , then the final temperature t is given by

100g of ice at 0C is mixed with 100g of water 80C The final temperature of the mixture will be

5 g of ice at 0^(@)C is dropped in a beaker containing 20 g of water at 40^(@)C . The final temperature will be

An amount of water of mass 20 g at 0^(@)C is mixed with 40 g of water at 10^(@)C . Final temperature of mixture is