The displacement of a particle executing S.H.M is given by `x= 0.01 sin 100pi (t + 0.05)`. The time period is

If the displacement of a particle executing S.H.M. is given by x = 0.24 sin (400 t + 0.5)m, then the maximum velocity of the particle is

The displacement of a particle executing S.H.M. is given by, y = 0.20 sin (100 t) cm. The maximum speed of the particle is

The displacement of a particle executing S.H.M. is given by, y = 0.20 sin (100 t) cm. The maximum speed of the particle is

The displacement of a particle executing S.H.M. is given by x = 0.34 sin (300 t + 0.68)m. Then its frequency is

The displacement of a particle performing a S.H.M. is given by x=0.5 "sin" 100 pi (t + 0.05) , where x is in metres and t is in second. Its periodic time in second is

The displacement of a particle executing SHM is given by Y=5 " sin "(4t+(pi)/(3)) If T is the time period and the mass of the particle is 2g, the kinetic energy of the particle When t= (T)/(4) is given by-

The displacement equation of a particle executing S.H.M is given by y=0.01 sin pi(t+0.005)m . Calculate the maximum velocity and displacement at the time of start of the motion.

The displacement of a particle executing S.H.M. is given by y = 0.25 sin 200t cm. The maximum speed of the particle is

The displacement of a particle executing SHM is given by y=0.5 sin100t cm . The maximum speed of the particle is

The motion of a particle executing S.H.M. is given by x= 0.01 sin 100 pi (t+.05) , where x is in metres and time is in seconds. The time period is