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Let n be the number of ways in which 5 b...

Let n be the number of ways in which 5 boys and 5 girls can stand in a queue in such a way that all the girls stand consecutively in the queue. Let m be the number in which 5 boys and 5 girls stand in such a way that exactly four girls stand consecutively in the queue. Then the value of `m/n` is ____

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`n= 6!*5!` eqn(1)
`m = .^5C_4(.^6C_2*2!)*4!*5!` eqn(2)
Dividing eqn (2) by eqn (1)
`m/n = (.^5C_4.^6C_2*2!*4!*5!)/(6!*5!)`
`= (5*3*5*2*4!*5!)/(6!*5!)`
`m/n = 5 `
answer
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