`(dy)/(dx)=(1)/(y+sin y)`

Solve :(dy)/(dx)=(1)/(y^(2)+sin y)

If the solution of the differential equation (dy)/(dx)=(1)/(x cos y+sin2y) is x=ce^(sin y+sin2y) is y), then the value of k

Solve (dy)/(dx)=(1+x^(2))/(y+sin y)

(dy)/(dx)=sin^(2)y

If (dy)/(dx)= y sin 2x, y(0)=1 , then solution is

If y = x sin y prove that (dy) / (dx) = (sin y) / ((1-x cos y))

If y,=x sin y, prove that (dy)/(dx),=(sin y)/((1-x cos y))

(dy) / (dx) = sin (x + y)

(dy) / (dx) -y = sin x

(dy)/(dx)=sin(x+y)