In a triangle `ABC, A(5,6), B(-1,4)` and centroid is at `(2, 4).` Then area of triangle formed by the mid points of sides of `ABC` is

Let A(0,-1),B(0,3)andC(2,1) be three points Let Delta_(1) be the area of the triangle ABC and Delta_(2) be the area of the triangle formed by the mid points of the sides of the triangle whose vertices are A,B and C such that (Delta_(1))/(Delta_(2))=(1)/(x) Find the value of x.

If ar( Delta ABC) = 16 cm^(2) then find the area of the triangle formed by joining the mid points of the sides of Delta ABC.

The sides of a triangle are 3cm,4cm and 5cm. The area (incm2) of the triangle formed by joining the mid-points of the sides of this triangle is (3)/(4) (b) (3)/(2) (c) 3 (d) 6

If Delta_(1) is the area of the triangle formed by the centroid and two vertices of a triangle Delta_(2) is the area of the triangle formed by the mid- point of the sides of the same triangle, then Delta_(1):Delta_(2) =

If Delta_(1) is the area of the triangle formed by the centroid and two vertices of a triangle Delta_(2) is the area of the triangle formed by the mid- point of the sides of the same triangle, then Delta_(1):Delta_(2) =

The coordinates of the vertex A of the triangle ABC are (2,5), if the centroid of the triangle is at (-2, 1), then the coordinates of the mid-point of the side BC are-

The coordinates of the vetex A of the triangle ABC are (2,5,-3), if centroid of the triangle is at (-2,1,3), find the coordinates of the mid points on the side BC.

The vertices of a Delta ABC are A (-5,-1), B (3,-5) , C (5,2). Show that the area of the Delta ABC is four times the area of the triangle formed by joining the mid-points of the sides of the triangle ABC.

In Delta ABC,A(5,6) and its centroid is (2,3) then mid point of the side BC is