The equation of motion of particle is `S=at^(2) +bt+c`.If the displcement after 1 sec is 20 m, velo0city after 2 sec is 30 m/ sec and the acceleration is `10m//se^(2)`, then

A particle moves on a line according to the law s=at^(2)+bt+c . If the displacement after 1 sec is 16 cm, the velocity after 2 sec is 24 cm/sec and acceleration is 8cm//sec^(2) , then

A particle moves on a line according to the law s=at^(2)+bt+c . If the displacement after 1 sec is 16 cm, the velocity after 2 sec is 24 cm/sec and acceleration is 8cm//sec^(2) , then

A particle moves on a line according to the law s = at^(2) + bt + c . If the displacement after one second is 16 cm, the velocity after 2 second is 24 cm/sec and the acceleration is 8cm//sec^(2) . Then (a,b,c)

A particle moves on a line according to the law s=at^2+bt+c . If the displacement after one second is 16 cm, the velocity after 2 second is 24 cm/sec and the acceleration is 8 cm/ sec^2 , then (a,b,c)=

In the above example, the velocity after 2 sec will be - (in m/sec)

The velocity v m/sec of particle is proportional to the cube of the time. If the velocity after 2 secs is 4m/sec, then v is equal to :

The equation motion of a particle in S.H.M. is a + 16 p^(2)x = 0 . In the equation .a. is the linear acceleration (in m//sec^(2) ) of the particle at a displacement .x. in meter. The time period of S H M in seconds is

The periodic time of a particle performing a linear S.H.M. is 12 sec. It starts from the mean position. After 2 seconds, its velocity is found to be pi cm//sec . What is the amplitude of S.H.M. ?