Find the acceleration of a particle placed on the surface of the earth at the equator, due to the earth rotation. The radius of earth is 6400 km and time period of revolution of the earth about its axis is 24 h.

Find the acceleration of a particle placed on the surface of the earth at the equator due to earth's rotation. The diameter of earth =12800 km and it takes 24 hour for the earth to complete one revolution about its axis.

Find the acceleration of a particle placed on the surface of the earth at the equator due to earth's rotation. The diameter of earth = 12800 km and it takes 24 hours for the earth to complete one revolution about its axis.

Find the acceleration of a particle placed on the surface of the earth at the equator due to earth's rotation. The diameter of earth =12800 km and it takes 24 hour for the earth to complete one revolution about its axis.

Find the acceleration of a particle placed on the surface of the earth at the equator due to earth's rotation. The diameter of erth =12800 km andit takes 24 hour for the earth to comlete one revolution about its axis.

What is the linear velocity of a body on the surface of the earth at the equator ? Given the radius of the earth is 6400 km . Period of rotation of the earth = 24 hours.

What is the linear velocity of a body on the surface of the earth at the equator ? Given the radius of the earth is 6400 km . Period of rotation of the earth = 24 hours.

What is the angular velocity of a body on'the surface of the earth at the equator ? Also find its linear velocity. Given radius of the earth is 6400 km. Period of rotation of the earth = 24 hours.

If the radius of earth shrinks to kR (k lt 1), where R is the radius of Earth, then the time period of rotation of Earth, about its axis will become

If the radius of earth shrinks to kR (k lt 1), where R is the radius of Earth, then the time period of rotation of Earth, about its axis will become