The coordinates of the two ends of latus rectum of a parabola are (8,1) and (-4,1) , find the equation of the parabola.

The coordinates of the two ends of latus rectum of a parabola are (3,4) and (3,0) ,find the equation of the parabola.

Two ends of the latus rectum of a parabola are (4,6) and (-2,6), then the equation of one of the parabola is

If two ends of latus rectum of a parabola are the points (3,6) and (5,6), then equation of the parabola is

The extremities of latus rectum of a parabola are (1,1) and (1,-1). Then the equation of the parabola can be

The extreme points of the latus rectum of a parabola are (7,5) and (7,3). Find the equation of the parabola and the points where it meets the coordinate axes.

The ends of latus rectum of parabola x^2+8y=0 are

The ends of latus rectum of parabola x^(2)+8y=0 are

Consider the parabola y^(2) = 4ax (i) Write the equation of the rectum and obtain the x co-ordinates of the point of intersection of latus rectum and the parabola. (ii) Find the area of the parabola bounded by the latus rectum.

The end points of latus rectum of the parabola x ^(2) =4ay are