The decomposition of `HNO_(3)` represented below attains equilibrium at a given `P_(eq.)` and `T`. If we start: `4HNO_(3(g))hArr4NO_(2(g))+2H_(2)O_((g))+O_(2(g))` with pure `HNO_(3)` having initial pressure `P_(i)`, then at equilibrium. Select the correct statement (`s`).

Assume that the decomposition of HNO_(3) can be represented by the following equation 4HNO_(3(g)) hArr 4NO_(2(g)) + 2H_(2) O_((g)) + O_(2(g)) and the reaction approaches equilibrium at 400K temperature and the copper turnning 0 atm pressure. At cquilibrium partial pressure of HNO_(3) is 2 atm. Calculate Kc in ("mole" //L)^(3) at 400 K.

Assume that the decomposition of HNO_(3) can be repersented by the following equation 4HNO_(3)(g)hArr4NO_(2)(g)+2H_(2)O(g)+O_(2)(g) and the reaction approaches wquilibrium at 400 K temperature and 30 atm pressure. At equilibrium partial pressure of HNO_(3) is 2 atm Calculate K_(c) in (mol//L-K) at 400K (Use:R=0.08atm-L//mol-K)

Assume that the decomposition of HNO_(3) can be repersented by the following equation 4HNO_(3)(g)hArr4NO_(2)(g)+2H_(2)O(g)+O_(2)(g) and the reaction approaches wquilibrium at 400 K temperature and 30 atm pressure. At equilibrium partial pressure of HNO_(3) is 2 atm Calculate K_(c) in (mol//L-K) at 400K (Use:R=0.08atm-L//mol-K)

In the reaction HNO_(3)+H_(2)O hArr H_(2)O ^(+) +NO_(3)^(-) the conjugate base of HNO_(3) is

The value of K_(P) for NH_(2)COONH_(4(s))hArr 2NH_(3(g))+CO_(2(g)) if the total pressure at equilibrium is P :-