In the figure shown mass of both, the spherical body and block is `m`. Moment of inertia of the spherical body about centre of mass is `2mR^(2)`. The spherical body rolls on the horizontal surface. There is no slipping at any surfaces in contact. The ratio of kinetic energy of the spherical body to that of block is

In the figure shown mass of both, the spherical body and blocks is m. Moment of inertia of the spherical body about centre of mass is 2mR^(2) . The spherical body rolls on the horizontal surface. There is no sliping between any two surfaces in contact. The ratio of kinetic energy of the spherical body to that of block is

A plank P is placed on a solid cylinder S , which rolls on a horizontal surface. The two are of equal mass. There is no slipping at any of the surfaces in contact. The ratio of kinetic energy of P to the kinetic energy of S is:

A spherical ball rolls on a horizontal surface without slipping .then the fraction of its total energy associated with rotatio is :

A body is rolling on a horizontal surface. Derive an equation for its kinetic energy.

A spherical ball rolls without slipping on a horizontal surface and its rotational kinetic energy is equal to the translational kinetic enregy.The body is :

For a body rolling along a level surface, without slipping the translational and rotational kinetic energies are in the ratio 2:1 . The body is