27 gm of `Al` reacts with excess of oxygen to give 4.59 gm of `Al_(2)O_(3)`. Calculate percentage yield of reaction.

Al_(2)O_(3) reacts with

Aluminium reacts with sulphure to form a aluminium sulphide . If 5.4 gm of Aluminium reacts with 12.8 gm sulphur gives 12 gm of aluminium sulphides , then the percent yield of the reaction is-

When heated, lithium reacts with nitrogen to gorm lithium nitride: Li(s)+N_(2)(g)rarrLi_(3)N_(s) When 21 gm of Li reacts with 280gm of N_(2) then 0.35 gm of Li_(3)N is formed. What is % yield of reaction.

Aluminium reacts with sulphure to form a aluminium sulphide . If 5.4 gm of Aluminium reacts with 12.8 gm sulphure gives 12 gm of aluminium sulphides , then the percent yield of the reaction is-

If half mole of oxygen combine with Al to form Al_(2)O_(3) the weight of Al used in the reaction is:

If 1 1/2 moles of oxygen combine with Al to form Al_(2)O_(3) the weight of Al used in the reaction is (Al=27)

If 1 1/2 moles of oxygen combine with Al to form Al_(2)O_(3) the weight of Al used in the reaction is (Al=27)

If 1 1/2 moles of oxygen combine with Al to form Al_(2)O_(3) the weight of Al used in the reaction is (Al=27)