In the figure 11.23, E is any point on median AD of a `Delta`ABC. Show that ar (ABE) = ar (ACE).

E is any point on median AD of a triangle ABC . Show that ar (ABE) = ar (ACE).

In Fig.9.23,E is any point on median AD of a Delta ABC Show that ar (ABE)=ar(ACE)

In the Given figure, E is any point on median AD of a triangle ABC Show that ar (ABE) = ar (ACE)

In the figure, E is any point on median AD of a triangleABC . Show that ar( triangleABE )= ar( triangleACE ).

In the adjoining figure,E is a point on the median AD of a Delta ABC. Show that ar (Delta ABE)=(Delta ACE)

E is any point on median AD of DeltaABC . If ar (DeltaABE) = 10 cm^2 then ar (DeltaACE) is :

E is any point on median AD of DeltaABC . If ar (DeltaABE) = 10 cm^2 then ar (DeltaACE) is :

E is any point on median AD of /_ABC .If ar(Delta ABE)=10cm^(2) then ar(Delta ACE) is

In a triangle ABC, E is the mid-point of median AD. Show that ar (BED) = (1)/(4) ar (ABC).

In a ABC,E is the mid-point of median AD Show that ar(BED)=(1)/(4) ar (ABC)