A particle with initial velocity u is moving with uniform acceleration (a). The distance moved by the particle in the `t^(th)` second is given by
`S=u+(1)/(2)a(2t-1)`
The dimensions of S must be

For a particle moving with constant acceleration, prove that the displacement in the n^(th) second is given by s_(n^(th)) = u + (a)/(2)(2n-1)

For a particle moving with constant acceleration, prove that the displacement in the n^(th) second is given by s_(n^(th)) = u + (a)/(2)(2n-1)

For a particle moving with constant acceleration, prove that the displacement in the n^(th) second is given by s_(n^(th)) = u + (a)/(2)(2n-1)

A particle is moving with initial velocity 1m/s and acceleration a=(4t+3)m/s^(2) . Find velocity of particle at t=2sec .

A particle having initial velocity u moves with a constant acceleration a for a time t. a. Find the displacement of the particle in the last 1 second . b. Evaluate it for u=5m//s, a=2m//s^2 and t=10s .

A particle having initial velocity u moves with a constant acceleration a for a time t. a. Find the displacement of the particle in the last 1 second . b. Evaluate it for u=5m//s, a=2m//s^2 and t=10s .

A particle having initial velocity u moves with a constant acceleration a for a time t. a. Find the displacement of the particle in the last 1 second . b. Evaluate it for u=5m//s, a=2m//s^2 and t=10s .

The distance travelled s in metres by a particle in t second is given by s=t^(3)+2t^(2)+t . The speed of the particle after 1s will be