Calculate the height of the Apple (India's first geostationary satellite) above the surface of the earth (Radius of the earth = 6400 km and `g = 9.8 ms^(-2)`)

A geostationary satellite is at a height h above the surface of earth. If earth radius is R -

Calculate the height at which a man's weight becomes ( 4//9) of his weight on the surface of the earth, if the radius of the earth is 6400km.

An earth's satellite makes a circle around the earth in 90 minutes. Calculate the height of the satellite above the earth's surface. Given radius of the earth is 6400 km and g=980 cms^(-2)

An Earth's satellite makes a circule around the Earth in 100 minutes. Calculate the height of the satellite above the Earth's surface. Given the radius of the Earth is 6400 km g = 10 ms^(-2) . Use pi^(2) = 10 .

A rocket is launched vetically from the surface of the earth with an initial velocity of 10 kms^(-1) . How for above the surface of the earth would it go ? Radius of the earth =6400 km and g=9.8 ms^(-2) .

An earth satellite makes a complete revolution around the earth in 120 minutes. If the orbit is circular calculate the height of satellite above the earth. Radius of the earth = 6400 km g = 9.8 ms^(-2) .

Find the value of 'g(i)' at a height of 100 km (ii) at height 6400 km from the surface of the earth. (Radius of the earth = 6400 km, g on the surface of the earth = 9.8 ms^(-2) .