A particle moving along a straight line has the relation `s=t^(3)+2t+3`, connecting the distance s describe by the particle in time t. Find the velocity and acceleration of the particle at t=4 sec.

A particle moving along a straight line has the relation s =t^2 +3, connecting the distance s described by the particle in time 1. Find the velocity and acceleration of the particle at t=4 seconds.

The equation of motion of a particle moving along a straight line is s=2t^(3)-9t^(2)+12t , where the units of s and t are centrimetre and second. The acceleration of the particle will be zero after

A particle moving along a straight line is at a distance S from a point O on the line in time t, where S = t^3-6t^2+8t+5 Find the velocity when the acceleration is 12 cm//sec^2

The displacement s of a particle at time t is given by s = t^3 -4 t^2 -5t. Find the velocity and acceleration at t=2 sec

A particle is moving in a straight line with the relation between the time and the distance in such a way that s=t^3-9t^2+24t-18 . The value of its velocity when the acceleration is zero is

A particle moves in a straight line with an acceleration a m/s^(2) at time t seconds,where a=-(1)/(t^(2)) .When t=1 the particle has a velocity of 3m/s .If the velocity of the particle at t=4s is (9)/(n)ms^(-1) The value of n is

A particle moves in a straight line with an acceleration a ms^-2 at time 't' seconds where a = - (1)/(t^2) When t = 1 the particle has a velocity of 3 ms^-1 . Find the velocity of the particle at t = 4 s .