In the circuit shown, switch `S` is closed at time `t = 0`. Find the current through the inductor as a function of time `t`.

Consider the circuit shown. Switch is closed at t=0. Find the current through the battery as a function of time. Initially capacitor was uncharged.

In given LR circuit the switch S is closed at time t=0 then

In given LR circuit the switch S is closed at time t=0 then

At t=0 , switch S is closed. Find time constant of the circuit and current through inductor as a function of time t .

In the circuit shown in figure switch S is closed at time t=0 Takin left to right current through the indcutor as apositive current, current through inductor varies with time as

In the circuit shown in figure switch S is closed at time t=0 Takin left to right current through the indcutor as apositive current, current through inductor varies with time as

In the circuit shown if Fig. the switch S is closed at time t = 0. The current through the capacitor and inductor will be equal at time t equal (given R = sqrt(L//C)

In the circuit shown if Fig. the switch S is closed at time t = 0. The current through the capacitor and inductor will be equal at time t equal (given R = sqrt(L//C)

In the circuit arrangement shown in figure, the switch S is closed at t = 0 . Find the current in the inductance as a function of time? Does the current through 10 Omega resistor vary with time or remains constant.

In the circuit arrangement shown in figure, the switch S is closed at t = 0 . Find the current in the inductance as a function of time? Does the current through 10 Omega resistor vary with time or remains constant.