The electric field in a region is given by `E = (4 axy sqrt(z))hat i + (2 ax^2 sqrt(z)) hat j + (ax^2 y// sqrt(z)) hat k`
where A is a positive constant. The equation of an equipotential surface will be of the form.

If the electric field in a region is given by vec(E) = 5 hat(i) + 4 hat(j)+ 9 hat(K) , then the electric flux through a surface of area 20 units lying in the y-z plane will be

The electric field in a region of space is given by, vec(E ) = E_(0) hat(i) + 2 E_(0) hat(j) where E_(0)= 100N//C . The flux of this field through a circular surface of radius 0.02m parallel to the Y-Z plane is nearly.

If the electric field is given by (6 hat(i) + 4 hat(j) + 4 hat(k)) , calculate the electric flux through a surface of area 20 units lying in Y-Z plane.

Find the angle made by the vector sqrt(2) hat (i) + hat (j) + hat (k) with the y - axis

The electric field in a region of space is given bar(E)=E_(0)hat i+2E_(0)hat j where E_(0)=100N/C .The flux of this field through a circular surface of radius 0.02m parallel to the Y-Z plane is nearly:

Electric flux through a surface of area 100m^2 lying in the xy plane is (in V-m) if vec E= hat i+ sqrt 2hat j + sqrt 3 hat k- .

A non-zero vector vec a is such that its projections along vectors ( hat i+ hat j)/(sqrt(2)),(- hat i+ hat j)/(sqrt(2)) and hat k are equal, then unit vector along vec a is a. (sqrt(2) hat j- hat k)/(sqrt(3)) b. ( hat j-sqrt(2) hat k)/(sqrt(3)) c. (sqrt(2))/(sqrt(3)) hat j+( hat k)/(sqrt(3)) d. ( hat j- hat k)/(sqrt(2))