When two displacement represented by `y_(1) = a sin (omega t)` and `y_(2) = b cos (omega t)` are superimposed, the motion is

when two displacements represented by y_(1) = a sin(omega t) and y_(2) = b cos (omega t) are superimposed the motion is

when two displacements represented by y_(1) = a sin(omega t) and y_(2) = b cos (omega t) are superimposed the motion is

When two displacements represented by Y_(1) = a sin (omega t) and Y_(2) = b cos (omega t) are superimposed the motion is

When two displacements represented by y_(1)= a sin(omega t)" and "y_(2)= b cos (omega t) are superimposed the motion is…….

When two displacement represented by y_1 = a sin t (omegat) and y_2 = b cos t (omegat) are superimposed the motion is

When the waves y_(1) = A sin omega t and y_(2) = A cos omega t are superposed, then resultant amplitude will be

Two wave are represented by equation y_(1) = a sin omega t and y_(2) = a cos omega t the first wave :-

Two waves represented as y_(1) = A_(1) sin omega t and y_(2) = A_(2) cos omega t superpose at a point in space. Find out the amplitude of the resultant wave at that point .

Two waves are represented by y_(1)= a sin (omega t + ( pi)/(6)) and y_(2) = a cos omega t . What will be their resultant amplitude

Two waves are represented by y_(1)= a sin (omega t + ( pi)/(6)) and y_(2) = a cos omega t . What will be their resultant amplitude