Home
Class 12
PHYSICS
In a series C-R circuit shown in figureu...

In a series `C-R` circuit shown in figureure, the applied voltage is `10 V` and the voltage across capacitor is found to`8 V`. The voltage across `R`, and the phase difference between current and the applied voltage will respectively be
.

Promotional Banner

Similar Questions

Explore conceptually related problems

In a series CR circuit shown in figure,the applied voltage is 10V and the voltage across capacitor is found to be 8V

In series LCR circuit, the phase difference between voltage across L and voltage across C is

In series LCR circuit, the phase difference between voltage across L and voltage across C is

In a series L-C circuit, the applied voltage is V_0. if omega is very low, then the voltage drop across the inductor V_L and capacitor V_C are .

In a series L-C circuit, the applied voltage is V_0. if omega is very low, then the voltage drop across the inductor V_L and capacitor V_C are .

In a LCR series circuit, if the phase difference between applied voltage and current is zero then

In a LCR series circuit,-if -the phase difference between applied voltage and current is zero then

In an L-C-R circuit, if V is the effective value of the applied voltage V_(R) is the voltage across R, V_(L) is the effective voltage across L, V_(C) is the effective voltage across C, then