A torque of `2.0xx10^(-4)Nm` is applied to produce an angular acceleration of `4"rad"s^(-2)` in a rotating body. What is the moment of inertia of the body?

A torque of 2.0 xx 10^(-4) Nm is applied to produce an angular acceleration of 4 "rad s"^(-2) in a rotating body. What is the moment of inertia of the body ?

A torque of 1500 Nm acting on a body produces an angular acceleration of 13.2 rad s^-2 . Find M.I of the body.

The torque needed to produce an angular acceleration of 18rad/ "sec"^2 in a body of moment of inertia 2.5kg- m^2 would be -

If a torque of magnitude 100 Nm acting on a rigid body produces an angular acceleration of 2 rad//s^(2) , then the moment of inertia of that body will be

A torque of 2000 Nm acting on a body produces an angular acceleration 2 rad/s^2 . Find thr M.I of body.

A torque of magnitude 2000 Nm acting on a body produces an angular acceleration of 20" rad/s"^(2) , The moment of inertia of the body is

A constant torque of 3.14 N.m is exerted on a pivoted wheel. If the angular acceleration of the wheel is 4pi"rad".s^(-2) , then the moment of inertia of the wheel is

The torque acting is 2000 Nm with an angular acceleration of 2rad//s^(2) . The moment of inertia of body is

A constant torque of 31.4 Nm is applied to a pivoted wheel. If the angular acceleration of the wheel is 2pi" rad/s"^(2) , then its moment of inertia is