The three initial and final positions of a man on the x-axis are given as
(i) (-3 m, 7 m) (ii) (7 m, -3 m)
(iii) (-7 m, 3 m)

The three initial and final position of a man on the x-axis are given (i) (-8 m, 7m) (ii) (7 m, -3 m) and (iii) ( 7 m, 3 m) Which pair gives the negative displacement?

The three initial and final position of a man on the X-axis are given as (i) (-8m, 7m) (ii) (7m, -3m) (iii) (-7m, 3m) Which pair gives the negative displacement ?

The three initial and final position of a man on the X-axis are given as (i) (-8m, 7m) (ii) (7m, -3m) (iii) (-7m, 3m) Which pair gives the negative displacement ?

Here are three pairs of initial and final positions, respectively, along an x axis. Which pairs give a negative displacement : (a) -3 m, +5 m, (b) -3 m, - 7 m, (c) 7m, -3 m ?

A particle can move only along x-axis. Three pairs of initial and final positions of particle at two successive times are given Pair Initial positions Final position 1 (-3)m (+5)m 2 (-3) m (-7)m 3 (+7) (-3), Find the sum of magnitudes of displacement in the pairs which give negative displacement in m.

The initial and final position vector for a particle are(-3m) hati+(2m)hatj+(8m)hatk and (9m)hati+(2m) hatj+(-8m)hatk respectively ,find the displacement of the particle.

The solution of the equation m-7=3 is m=

If m=2 find the value of : (i) m-2 (ii) 3m-5 (iii) 9-5m (iv) 3m^2-2m-7