A black body is at a temperature of 2880 K. The energy of radiation emitted by this object with wavelength between 4990 A and 5000A is `E_(1)` , and that between 9990 A and 10000 A is `E_(2)` . Find the ratio of `E_(2)` and `E_(1)`.

A blackbody is at a temperature of 2880K. The energy of radiation emitted by this object with wavelength between 499nm and 500nm is U_1 , between 999nm and 1000nm is U_2 and between 1499 nm and 1500 nm is U_3 . The Wien constant b=2.88xx10^6nmK . Then

A blackbody is at a temperature of 2880K. The energy of radiation emitted by this object with wavelength between 499nm and 500nm is U_1 , between 999nm and 1000nm is U_2 and between 1499 nm and 1500 nm is U_3 . The Wien constant b=2.88xx10^6nmK . Then

Compare the energies of two radiations E_(1) with wavelength 800 nm and E_(2) with wavelength 400 nm.

Compare the energies of two radiations E_(1) with wavelength 800 nm and E_(2) with wavelength 400 nm.

If the rate of emission of radiation by a body at temperature TK is E then graph between log E and log T will be .

A black body at a high temperature T radiates energy at the rate of E. When the temperature falls to T/2,the radiated energy will be