If the area enclosed by curve `y=f(x)a n dy=x^2+2` between the abscissa `x=2a n dx=alpha,alpha>2,` is `(alpha^3-4alpha^2+8)s qdot` unit. It is known that curve `y=f(x)` lies below the parabola `y=x^2+2.`

If the area enclosed by curve y=f(x) and y=x^2+2 between the abscissa x=2 and x=alpha,alpha>2, is (alpha^3-4alpha^2+8)s qdot unit. It is known that curve y=f(x) lies below the parabola y=x^2+2. Find f(x)

If the area enclosed by curve y=f(x) and y=x^(2)+2 between the abscissa x=2 and x=alpha,alpha>2, is (alpha^(3)-4 alpha^(2)+8)sq. unit.It is known that curve y=f(x) lies below the parabola y=x^(2)+2

The area enclosed by the curves x y^2=a^2(a-x)a n d(a-x)y^2=a^2x is

The area enclosed by the curves x y^2=a^2(a-x)a n d(a-x)y^2=a^2x is

The area enclosed between the curves y=x^2 and x=y^2 is :

Find the value of alpha for which the point (alpha -1, alpha) lies inside the parabola y^(2) = 4x .

If f(x) is a non - negative function such that the area bounded by y=f(x), x - axis and the lines x = 0 and x=alpha is 4alpha sin alpha+2 sq. Units ( AA alpha in [0, pi] ), then the value of f((pi)/(2)) is equal to

If f(x) is a non - negative function such that the area bounded by y=f(x), x - axis and the lines x = 0 and x=alpha is 4alpha sin alpha+2 sq. Units ( AA alpha in [0, pi] ), then the value of f((pi)/(2)) is equal to

Find alpha if (alpha, alpha^2) lies inside the triangle having sides along the lines 2x+3y=1, x+2y-3=0, 6y=5x-1.