`(2a^(2) + a - 1)/(a + 1) + (3a^(2) + 5a + 2)/(3a + 2) + (4 - a^(2))/(a+2) =..`

5a - [a^(2) - {2a (1 - a + 4a^(2)) - 3a(a^(2) - 5a -3)}] - 8a

What will come next in the series given below ? 1 1 2 1 2 3 1 2 3 4 1 2 3 4 5 1 2 3 4 5 1 2 3 4 5 6 1 2 3 4 5 6 7 1 2 3 4 5 1) 1 2) 5 3) 6 4) 2 5) None of these

Find 1/2 , (1^2 + 2^2) / 3 , (1^2 + 2^2 + 3^2) / 4 , (1^2 + 2^2 + 3^2 + 4^2) / 5 , ……. Upto 'n' terms.

If x=(1)/(1^(2))+(1)/(3^(2))+(1)/(5^(2))+ . . . y=(1)/(1^(2))+(3)/(2^(2))+(1)/(3^(2))+(3)/(4^(2))+ . . . . z=(1)/(1^(2))-(1)/(2^(2))+(1)/(3^(2))-(1)/(4^(2))+ . . .then

Take away :(5a^(2))/(2)+(3a^(3))/(2)+(a)/(3)-(6)/(5) om (1)/(3)a^(3)-(3)/(4)a^(2)-(5)/(2)