Calculate the equilibrium constant for the reaction
`Fe+CuSO_4 Given `E_(Fe//Fe^(2+))^0=0.44V, E^0(Cu//Cu^(2+))=-0.337V`

Calculate the equilibrium constant for the reaction Fe+ CuSO_4 → FeSO_4 + Cu at 25^(@)C Given E_(Fe//Fe^(2+))^0=0.44V, E^0(Cu//Cu^(2+))=-0.337V

Calculate the equilibrium constant for the reaction Fe + CuSO_4 ⇌ FeSO_4 + Cu at 25°C. (Given E°(OP/Fe) = 0.5 V°, E°(OP/Cu) = -0.4 V)

Calculate the equilibrium constant for the reaction : Fe^(2+)+Ce^(4+)hArr Fe^(3+)+Ce^(3+) Given, E_(Ca^(4+)//Ce^(3+))^(@)=1.44V and E_(Fe^(3+)//Fe^(2+))^(@)=0.68V

Calculate the equilibrium constant for the reaction : Fe^(2+)+Ce^(4+)hArr Fe^(3+)+Ce^(3+) Given, E_(Ca^(4+)//Ce^(3+))^(@)=1.44V and E_(Fe^(3+)//Fe^(2+))^(@)=0.68V

Calculate the equilibrium constant for the reaction : Fe(s)Cd^(2+)(aq)harrFe^(2+)(aq)+Cd(s) ("Given" E_(cd^(2+)//Cd)^(@)=-0.40 V, E_(Fe^(2+)//Fe)^(@)=-0.44 V)

Calculate the equilibrium constant for the reaction Fe(s)+Cd2+(aq)⇔Fe2+(aq)+Cd(s) (Given : E∘Cd2+∣Cd=0.40V,E∘Fe2+∣Fe=−0.44V).

Calculate the equilibrium constant for the reaction. Fe(s) + Cd^(2+) (aq) hArr Fe^(2+)(aq) + Cd(s) [ Given, E_(Cd^(2+) //Cd)^(@) = - 0.40V , E_(Fe^(2+)//Fe)^(@) = - 0.44 V ]

Calculate the equilibrium constant for the following reaction. Fe(s)+2Ag^+(aq) rarr 2Ag(s)+Fe^(2+)(aq) E_(Fe^(2+)//Fe)^@=-0.44V,E_(Ag^+//Ag)^=+0.80V .