`(1-i)(1+2i)(1-3i)=`

Reduce ((1)/(1+2i)+(3)/(1-i))((3-2i)/(1+3i)) to the form (a + ib).

Perform the following by the indicated operations. Express the result in the form x + iy,where x, y are real numbers i = sqrt(-1) : ((1-i)(2-i)(3-i))/(1+i) .

If one root of x^(2)-(3+2i)x+(1+3i)=0 is 1+i then the other root is A) 1-i B) 2+i C) 3+i D) 1+3i

1+(1+i)+(1+i)^(2)+(1+i)^(3)=

(1) The value of (1+i)(1+i^2)(1+i^3)(1+i^4) is

The value of (1+i)(1+i)^2(1+i)^3(1+i^4) is:

The value of (1+i)(1+i^2)(1+i^3)(1+i^4) is a. 2 b. 0 c. 1 d. i

Reduce to the form A + IB ((1-i)^2-(1+i)^2)/((1-i)^3+(1+i)^3)

Express the following in the standard form a+i b :(1/(1-2i)+3/(1+i))((3+4i)/(2-4i))