A surface `S=10hatj` is kept in an electric field of `vecE=3hati+5hatj+6hatk`. How much electric flux will come out through the surface?

A surface s =10hatj is kept in an electric field. E = 2hati+4hatj+7hatk . How must electric flux will come out through the surface ?

In vacuum (i) find out the electric flux across an area vec S = 10 hatj placed in an electric field vec E = 2 hati + 4 hatj + 7 hatk , (ii) How many electric charges are to be placed at a point such that 4400 number of electric lines of forces with emerge from that point ? (iii) What will be the electric flux through any one of the faces of a cube of side 10 cm if a charge of 1 esu is placed at the centre of the cube ?

The electric flux coming out of the equi-potential surface is -

In a region, the intensity of an electric field is given by vecE=2hati+3hatj+hatk in NC^(-1) . The electric flux through a surface vecS=10hatim^(2) in the region is

In a region of space, the electric field is given by vecE = 8hati + 4hatj + 3hatk . The electric flux through a surface of area 100 units in the xy plane is

In a region of space, the electric field is given by vecE = 8hati + 4hatj + 3hatk . The electric flux through a surface of area 100 units in the xy plane is

If an electric field is given by 10hati+3hatj+4hatk calculate the electric flux through a surface of area 10 units lying in yz plane

If an electric field is given by 10hati+3hatj+4hatk calculate the electric flux through a surface of area 10 units lying in yz plane

The electric field in the region of the space is vecE = (5hati + 2hatj + 3hatk)NC^(-1) . The electric flux passing through a surface of area 50m^2 placed in X-Y plane inside the electric field is.......